Refer to the arrangement of arrangement of charges in figure and a gaussian surface of radius R with Q charge at the center. Then 

(a) Total flux through the surface of the sphere is - Q ε 0 .

(b) Field on the surface of the sphere of the sphere is -Q/4 π ε 0R2.

(c) Flux through the surface of sphere due to 5Q is zero.

(d) Field on the surface of sphere due to -2Q is same everywhere

 

0 1 View | Posted 4 months ago
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  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Multiple Choice Questions as classified in NCERT Exemplar

    Answer – (a, c)

    Explanation- Gauss's law states that the total electric flux of an enclosed surface is given by q/? 0, where q is the charge enclosed by the surface.

    So total charge inside the surface is = Q-2Q = -Q

    Therefore total flux through the surface of the sphere = -Q/? 0

    Now, charge 5Q is lies outside the surface, thus it makes no contribution to electric flux through the given surface. So both option a and c are true.

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