Sand is being dropped from a stationary dropper at a rate of 0.5 kgs-1 on a conveyor belt moving with a velocity of 5ms-1. The power needed to keep the belt moving with the same velocity will be:

Option 1 - <p>1.25 W</p>
Option 2 - <p>2.5 W</p>
Option 3 - <p>6.25 W</p>
Option 4 - <p>12.5 W</p>
4 Views|Posted 6 months ago
Asked by Shiksha User
2 Answers
A
6 months ago
Correct Option - 4
Detailed Solution:

P = F . v = v d P d t = v 2 ( d m d t ) = 0 . 5 * 2 5 = 1 2 . 5 W

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A
6 months ago

P = F ? . v ? = v d P d t = v 2 ( d m d t ) = 0 . 5 * 2 5 = 1 2 . 5 W

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Physics Motion in Straight Line 2025

Physics Motion in Straight Line 2025

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