Show that for a particle executing S.H.M, velocity and displacement have a phase difference of π/2.

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Answered by

Payal Gupta | Contributor-Level 10

4 months ago

This is a multiple choice answer as classified in NCERT Exemplar

As we know x= acoswt

V =dx/dt= a (-sinwt)w=-wasinwt

V=-wasinwt

= wacos ( $\frac{π}{2} + w t$ )

Phase of velocity = $\frac{π}{2} + w t$

So difference in phse of velocity to that of phase of displacement = $\frac{π}{2} + w t - w t$ = $\frac{π}{2}$

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