Show that when a string fixed at its two ends vibrates in 1 loop, 2 loops, 3 loops and 4 loops, the frequencies are in the ratio 1:2:3:4.

2 Views|Posted 7 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Payal Gupta | Contributor-Level 10

7 months ago

This is a short answer type question as classified in NCERT Exemplar

Let there are n number of loops in the string

length corresponding each loop is $\frac{λ}{2}$

So we can write L= $\frac{n λ}{2}$

$λ = \frac{2 L}{n}$

v/ $v$ =2L/n

so frequency $v = \frac{n}{2 L}$ v= $\frac{n}{2 L} \sqrt[]{\frac{T}{μ}}$

v $\propto n$

so $v_{1} : v_{2} : v_{3} : v_{4} = n_{1} : n_{2} : n_{3} : n_{4}$

= 1:2:3:4

Upvote

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Physics NCERT Exemplar Solutions Class 11th Chapter Fifteen 2025

View Exam Details

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering