Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01cm³ of oleic acid per cm³ of the solution. Then you make a thin film of this solution (monomolecular thickness) of area 4cm² by considering 100 spherical drops of radius ³√(3/(40π)) × 10⁻³ cm. Then the thickness of oleic acid will be x × 10⁻¹⁴ m. Where x is ______.
Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01cm³ of oleic acid per cm³ of the solution. Then you make a thin film of this solution (monomolecular thickness) of area 4cm² by considering 100 spherical drops of radius ³√(3/(40π)) × 10⁻³ cm. Then the thickness of oleic acid will be x × 10⁻¹⁴ m. Where x is ______.
Asked by Shiksha User
-
1 Answer
-
4t = 100 * (4/3)π * (40π * 10? * 0.01)³
t = 2.5 * 10? ¹¹ cm = 2.5 * 10? ¹³ m
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 686k Reviews
- 1800k Answers