Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01cm³ of oleic acid per cm³ of the solution. Then you make a thin film of this solution (monomolecular thickness) of area 4cm² by considering 100 spherical drops of radius ³√(3/(40π)) * 10⁻³ cm. Then the thickness of oleic acid will be x * 10⁻¹⁴ m. Where x is ______.

6 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago

4t = 100 * (4/3)π * (40π * 10? * 0.01)³
t = 2.5 * 10? ¹¹ cm = 2.5 * 10? ¹³ m

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering