The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from x = 0 to x = b. Identify the graph the variation of different quantities with distance.

 

Option 1 - <p>A – Flux, B – EMF, C – Power dissipated</p>
Option 2 - <p>A – EMF, B – Power dissipated, C – Flux</p>
Option 3 - <p>A – Power dissipated, B – Flux, C – EMF</p>
Option 4 - <p>A – Flux, B – Power dissipated, C – EMF</p>
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6 months ago
Correct Option - 1
Detailed Solution:

When arm PQ of a rectangular conductor is moving from x = 0 to x = b, the flux ( ? = a x ) linked with loop increases and while moving from x = b to x = 2b and from x = 2b to x = b, ( ? = a b ) flux remains constant and then flux ( ? = a x ) decreases to zero as it moves from x = b to x = 0.

e i n = d ? d t = a d x d t = a v Induced emf

P = ( e i n ) 2 R Power dissipa

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Yes, the cube, which is a closed surface containing only one electric dipole will make electric flux zero. This follows Gauss's Law when the total charge inside it is zero. The field lines entering the surface will exit, and that would result in zero net flux. 

 

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The magnitude of each charge and the distance that separates them. 

Gauss Law is only concerned with the total enclosed charge that finally tells us the total flux. The charges outside may change field patterns. They not affect the total flux. It's actually incorrect to assume the field due to the external charges should also affect the flux through the Gaussian sur

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Gauss Law does not directly give the electric field in all cases. It can only be used in calculations for symmetrical surfaces: spherical, cylindrical, or planar. 

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Physics Electromagnetic Induction 2021

Physics Electromagnetic Induction 2021

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