The average translational kinetic energy of N₂ gas molecules at_________°C becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt. (Given k_B = 1.38 × 10^-23 J/K) (Fill the nearest integer).

<p>K.E. energy of electron = eV</p><p>Translational K.E. of N₂ = &lt;!- [if gte mso 9]-&gt; &lt;!- [endif]-&gt;&nbsp;<span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mi>K</mi> <mi>T</mi> </mrow> </math> </span></p><p>So eV =<span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mi>K</mi> <mi>T</mi> </mrow> </math> </span> &lt;!- [if gte mso 9]-&gt; &lt;!- [endif]-&gt;&nbsp;</p><p><span contenteditable="false"> <math> <mrow> <mn>1</mn> <mo>.</mo> <mn>6</mn> <mo>×</mo> <mn>1</mn> <msup> <mrow> <mn>0</mn> </mrow> <mrow> <mo>−</mo> <mn>1</mn> <mn>9</mn> </mrow> </msup> <mo>×</mo> <mn>0</mn> <mo>.</mo> <mn>1</mn> <mo>=</mo> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mo>×</mo> <mn>1</mn> <mo>.</mo> <mn>3</mn> <mn>8</mn> <mo>×</mo> <mn>1</mn> <msup> <mrow> <mn>0</mn> </mrow> <mrow> <mo>−</mo> <mn>2</mn> <mn>3</mn> </mrow> </msup> <mo>×</mo> <mi>T</mi> </mrow> </math> </span> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&lt;!- [if gte mso 9]-&gt; &lt;!- [endif]-&gt;&nbsp;</p><p>T = 773 – 273 = 500°C</p>

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