The bulk modulus of a liquid is 3 * 1010 Nm-2. The pressure required to reduce the volume of liquid by 2% is :

We know, Δ P = − B Δ v v [ ? B = − Δ P ( v Δ v ) ] ⇒ 1 0 0 * Δ P = − B x [ Δ v v * 1 0 0 ] ⇒ 1 0 0 + Δ P = − 3 * 1 0 1 0 ( − 2 ) Δ P = 6 * 1 0 1 0 1 0 0 Δ P = 6 * 1 0 8 N m − 2

**The bulk modulus of a liquid is 3 * 10¹⁰ Nm^-2. The pressure required to reduce the volume of liquid by 2% is :**

Option 1 - 3 × 108 Nm-2

Option 2 - 9 × 108 Nm-2

Option 3 - 6 × 108 Nm-2

Option 4 - 12 × 108 Nm-2

6 Views|Posted 8 months ago

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Vishal Baghel | Contributor-Level 10

8 months ago

Correct Option - 3

Detailed Solution:

We know, $Δ P = - B \frac{Δ v}{v}$ $[? B = - Δ P (\frac{v}{Δ v})]$

$\Rightarrow 100 * Δ P = - B x [\frac{Δ v}{v} * 100]$

$\Rightarrow 100 + Δ P = - 3 * 1 0^{10} (- 2)$

$Δ P = \frac{6 * 1 0^{10}}{100}$

$Δ P = 6 * 1 0^{8} N m^{- 2}$ $\frac{}{}$

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Physics Mechanical Properties of Solids 2025

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