The correct graph between logeR
and loge(θ– θ0) during cooling of a body may be (R is the rate of cooling and q0 is surrounding temperature)
The correct graph between logeR and loge(θ– θ0) during cooling of a body may be (R is the rate of cooling and q0 is surrounding temperature)
Option 1 -
A
Option 2 -
B
Option 3 -
C
Option 4 -
D
-
1 Answer
-
Correct Option - 1
Detailed Solution:
Similar Questions for you
Heat is path dependent so path function but internal energy does not depend on path chosen.
Work Area
->W =
= 1200J
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers