The current flowing through and ac circuit is given by I = 5sin(12πt) A

How long will the current take to reach the peak value staring from zero?

Option 1 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>6</mn> <mn>0</mn> </mrow> </mfrac> <mi>s</mi> </mrow> </math>

Option 2 - 60 s

Option 3 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>1</mn> <mn>2</mn> <mn>0</mn> </mrow> </mfrac> <mi>s</mi> </mrow> </math>

Option 4 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> <mn>4</mn> <mn>0</mn> </mrow> </mfrac> <mi>s</mi> </mrow> </math>

11 Views|Posted 6 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 4

Detailed Solution:

Given, I = 5 sin (120πt), $ω$ = 120

$T = \frac{2 π}{ω}$

$T = \frac{2 π}{120 π} = \frac{1}{60} s e c, \frac{T}{4} = \frac{1}{60 * 4} = \frac{1}{240} s e c$

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The current flowing through and ac circuit is given by I = 5sin(12πt) A How long will the current take to reach the peak value staring from zero?

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