The diameter of a spherical bob is measured using a vernier calipers. 9 divisions of the main scale, in the vernier caliper, are equal to 10 divisions of vernier scale. One main scale division is 1mm. The main scale reading is 10mm and 8^th division of vernier scale was found to coincide exactly with one of the main scale division. If the given vernier calipers has positive zero error of 0.04cm, then the radius of the bob is______ × 10^-2cm.

<p>From question :</p><p>9MSD = 10VSD</p><p>LC = 1MSD – 1VSD = 1MSD - <span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>9</mn> </mrow> <mrow> <mn>1</mn> <mn>0</mn> </mrow> </mfrac> <mi>M</mi> <mi>S</mi> <mi>D</mi> <mo>=</mo> <mn>0</mn> <mo>.</mo> <mn>1</mn> <mi>M</mi> <mi>S</mi> <mi>D</mi> <mo>=</mo> <mn>0</mn> <mo>.</mo> <mn>1</mn> <mo>*</mo> <mn>1</mn> <mi>m</mi> <mi>m</mi> <mo>=</mo> <mn>0</mn> <mo>.</mo> <mn>1</mn> <mi>m</mi> <mi>m</mi> </mrow> </math> </span>&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1815999232"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;</p><p>Reading = 10mm + 8 * 0.1 mm = 10.8 mm</p><p>Final reading = 10.8 mm – 0.04 mm = 10.4 mm = 104 * 10^-2 cm</p><p>So radius = 52 * 10^-2 cm</p>

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