The displacement time graph of a particle executing SHM is given in figure: (sketch is schematic and not to scale)

Which of the following statements is/are true for this motion?
(a) The force is zero at t = 3T/4
(b) The acceleration is maximum at t = T
(c) The speed is maximum at t = T/4
(d) The P.E. is equal to K.E. of the oscillation at t = T/2

 

Option 1 - <p>(a), (b) and (d)</p>
Option 2 - <p>(a) and (d)</p>
Option 3 - <p>(a), (b) and (c)</p>
Option 4 - <p>(b), (c) and (d)</p>
16 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
7 months ago
Correct Option - 3
Detailed Solution:

F = MA = m (-ω²x). F=0 at x=0 (t=T/4, 3T/4.). (a) is correct.
Acceleration is max at extremes (t=0, T/2, T.). (b) is correct.
Speed is max at mean position (t=T/4, 3T/4.). (c) is correct.
PE=KE at x=A/√2. t=T/8. (d) is incorrect.

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics Units and Measurement 2025

Physics Units and Measurement 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering