The distance between an object and a screen is 100 cm. A lens can produce real image of the object on the screen for two different positions between the screen and the object. The distance between these two positions is 40 cm. If the power of the lens is close to (N/100) D where N is an integer, the value of N is
The distance between an object and a screen is 100 cm. A lens can produce real image of the object on the screen for two different positions between the screen and the object. The distance between these two positions is 40 cm. If the power of the lens is close to (N/100) D where N is an integer, the value of N is
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1 Answer
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P = 1/f = (N/100)D
2x + 40 = 100
x = 30 cm
100 – x = 70 cm
1/v - 1/u = 1/f
1/70 - 1/ (-30) = 1/f
1/f = 1/70 + 1/30 = (3+7)/210 = 1/21
f = 21 cm = 0.21M
Power = 1/f = 1/0.21; D = (100)/21
N/100 D = 100/21
N = 10000/21 = 476.19
N = 476
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