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The efficiency of a Carnot’s engine, working between stem point and ice point, will be:

Option 1 -

26.81%

Option 2 -

37.81%

Option 3 -

47.81%

Option 4 -

57.81%

0 2 Views | Posted 2 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    2 weeks ago
    Correct Option - 1


    Detailed Solution:

    Steam point (T1) = 100°C = 273 + 100 = 373 K

    Ice point (T2) = 0°C = 273 K

    η = ( 1 − T 2 T 1 ) × 1 0 0 = ( 1 − 2 7 3 3 7 3 ) × 1 0 0 = 2 6 . 8 1 %  

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