The electric field intensity produced by the radiation coming from a 100W bulb at a distance of 3 m is E. The electric field intensity produced by the radiation coming from 60 W at the same distance is √(x/5) E. Where the value of x = ______.
The electric field intensity produced by the radiation coming from a 100W bulb at a distance of 3 m is E. The electric field intensity produced by the radiation coming from 60 W at the same distance is √(x/5) E. Where the value of x = ______.
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1 Answer
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Electric field squared is proportional to the power P of the bulb (E² ∝ P).
(E' / E)² = (60 / 100) ⇒ E' = E * √* (3/5)*
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