The electromagnetic waves travel in medium at a speed of 2.0 × 108 m/s. The relative permeability of the medium is 1.0. The relative permittivity of the medium will be:

we know,  C = 1 μ 0 ∈ o = 3 × 1 0 8 , G i v e n , ∈ r = 1 v = 1 μ 0 ∈ r ∈ o μ r = 2 × 1 0 8  ⇒ 3 × 1 0 8 2 × 1 0 8 = ∈ r μ r  = ( 1 . 5 ) 2 = ∈ r μ r  μ r = 2 . 2 5

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Physics Class 12th Physics Electromagnetic Waves

The electromagnetic waves travel in medium at a speed of 2.0 × 10⁸ m/s. The relative permeability of the medium is 1.0. The relative permittivity of the medium will be:

Option 1 -

2.25

Option 2 -

4.25

Option 3 -

6.25

Option 4 -

8.25

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 1

Detailed Solution:

we know, $C = \frac{1}{\sqrt[]{μ_{0} \in o}} = 3 \times 1 0^{8}, G i v e n, \in_{r} = 1$

$v = \frac{1}{\sqrt[]{μ_{0} \in_{r} \in_{o} μ_{r}}} = 2 \times 1 0^{8}$

$\Rightarrow \frac{3 \times 1 0^{8}}{2 \times 1 0^{8}} = \sqrt[]{\in_{r} μ_{r}}$

$= {(1.5)}^{2} = \in_{r} μ_{r}$

$μ_{r} = 2.25$

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The electromagnetic waves travel in medium at a speed of 2.0 × 10⁸ m/s. The relative permeability of the medium is 1.0. The relative permittivity of the medium will be:

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