The equivalent capacitance between points A and B in below shown figure will be…………. $$ $\mu F.$

 

ceq = $\frac{24\times 8}{32}=6\mu F$

 

 

<p>ceq = <span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>2</mn> <mn>4</mn> <mo>×</mo> <mn>8</mn> </mrow> <mrow> <mn>3</mn> <mn>2</mn> </mrow> </mfrac> <mo>=</mo> <mn>6</mn> <mi>μ</mi> <mi>F</mi> </mrow> </math> </span></p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1757398467phpJTe8w1.jpeg" alt="" width="382" height="301" loading="lazy"></picture></div></div><p>&nbsp;</p><p>&nbsp;</p>

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