The figure shows a region of length 'l' with a uniform magnetic field of 0.3 T in it and a proton entering the region with velocity 4 × 10⁵ ms⁻¹ making an angle 60° with the field. If the proton completes 10 revolution by the time it cross the region shown, 'l' is close to (mass of proton = 1.67 × 10⁻²⁷ kg, charge of the proton = 1.6 × 10⁻¹⁹C)
The figure shows a region of length 'l' with a uniform magnetic field of 0.3 T in it and a proton entering the region with velocity 4 × 10⁵ ms⁻¹ making an angle 60° with the field. If the proton completes 10 revolution by the time it cross the region shown, 'l' is close to (mass of proton = 1.67 × 10⁻²⁷ kg, charge of the proton = 1.6 × 10⁻¹⁹C)
Option 1 -
0.44 m
Option 2 -
0.11 m
Option 3 -
0.88 m
Option 4 -
0.22 m
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:l = 10 × pitch = 10 × (2πmvcosθ/qB)
= 20π × 1.67×10? ²? × 4×10? × (1/2) / (1.6×10? ¹? × 0.3) = 0.44 m
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