The force required to stretch a steel wire of cross section 4 cm2 to 1.02 times its length would be (Y = 2*1011 N m–2)
The force required to stretch a steel wire of cross section 4 cm2 to 1.02 times its length would be (Y = 2*1011 N m–2)
Option 1 - <p>1.6*10<sup>6</sup> N</p>
Option 2 - <p>1.6*10<sup>–6</sup> N</p>
Option 3 - <p>1.6*10<sup>–7</sup> N</p>
Option 4 - <p>1.6*10<sup>7</sup> N</p>
1 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
Answered by
4 months ago
Correct Option - 1
Detailed Solution:
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics Mechanical Properties of Fluids 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering






