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The force required to stretch a steel wire of cross section 4 cm2 to 1.02 times its length would be (Y = 2*1011 N m–2)

Option 1 -

1.6*106 N

Option 2 -

1.6*10–6 N

Option 3 -

1.6*10–7 N

Option 4 -

1.6*107 N

0 1 View | Posted a week ago
Asked by Shiksha User

  • 1 Answer

  • Correct Option - 1


    Detailed Solution:
    Kimdly go thorugh the solution

     

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