The gravitational force between a hollow spherical shell (of radius R and uniform density) and a point mass is F. Show the nature of F vs r graph where r is the distance of the point from the centre of the hollow spherical shell of uniform density.

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Explanation- As density of the shell is constant

So mass of shell = density (volume)

= $\rho \left(\frac{4}{3}\pi R^3\right)=M$

If we consider shell is uniform so F=gravitational force =GMm/r²

F=0 for r

= GM/r² for r>R

Variation of f verses r

<p>This is a &nbsp;Short Answer Type Questions as classified in NCERT Exemplar</p><p><strong>Explanation-</strong> As density of the shell is constant</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1745474081phpAyQOiW_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1745474081phpAyQOiW.jpeg" alt="" width="257" height="115"></picture></div></div><p>So mass of shell = density (volume)</p><p>=<span contenteditable="false"> <math> <mi>ρ</mi> <mfenced separators="|"> <mrow> <mrow> <mfrac> <mrow> <mrow> <mn>4</mn> </mrow> </mrow> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> </mfrac> <mi>π</mi> <msup> <mrow> <mrow> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> </msup> </mrow> </mrow> </mfenced> <mo>=</mo> <mi>M</mi> </math> </span></p><p>If we consider shell is uniform so F=gravitational force =GMm/r²</p><p>F=0 for r</p><p>= GM/r² for r&gt;R</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1745474106phpe4Mer0_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1745474106phpe4Mer0.jpeg" alt="" width="155" height="123"></picture></div></div><p>Variation of f verses r</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment