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The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to ( 1 / 16 ) th    of its initial value?

Option 1 -

80 minutes

Option 2 -

20 minutes

Option 3 -

40 minutes

Option 4 -

60 minutes

0 1 View | Posted 4 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    4 weeks ago
    Correct Option - 1


    Detailed Solution:

    N N 0 = 1 16 = 1 2 t T 1 / 2

    t = 4 T 1 / 2 = 20 * 4 = 80   minutes  

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