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The length of a second’s pendulum on the surface of Earth is 1m. What will be the length of a second’s pendulum on the moon?

0 3 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a multiple choice answer as classified in NCERT Exemplar

    Time period of simple pendulum T=2s

    For simple pendulum T= 2 π l g  where l is length and g = acceleration due to gravity.

    Te=2 π l e g e

    On the surface of the moon Tm= 2 π l m g m

    T e T m = 2 π 2 π l e g e × g m l m

    Te=Tm to maintain the second’s pendulum time period

    1= l e g e × g m l m …………….1

    But the acceleration due to gravity at moon is 1/6 of the acceleration due to gravity at earth,

    gm= g e 6

    squaring equation 1 and putting this value

    1= l e l m × g e / 6 g e = l e l m × 1 6

    lm=1/6le = 1/6 m

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