The mass density of a spherical galaxy varies as K/r over a large distance 'r' from its center. In that region, a small star is in a circular orbit of radius R. Then the period of revolution, T depends on R as:

Option 1 - <p>T ∝ R</p>
Option 2 - <p>T² ∝ R³<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>T² ∝ 1/R³</p>
Option 4 - <p>T² ∝ R</p>
3 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
7 months ago
Correct Option - 4
Detailed Solution:

M = ∫ ρdV
M = ∫??? (k/r) 4πr²dr
M = 4πkR?²/2 = 2πkR?²
F? = GMm/R?² = 2ω?²R

 

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Physics Gravitation 2025

Physics Gravitation 2025

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