The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are 3 * 10⁻⁷ m and 600 m/s, respectively. Find the frequency of its collisions.

Option 1 - <p>2 × 10¹⁰/s</p>
Option 2 - <p>9 × 10⁵/s<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>2 × 10⁹/s</p>
Option 4 - <p>5 × 10⁸/s</p>
41 Views|Posted 4 months ago
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1 Answer
A
5 months ago
Correct Option - 3
Detailed Solution:

Frequency of collisions = 1/T = Vavg/λ = 600/ (3 * 10? ) = 2 * 10? sec? ¹

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physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

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