The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm2 . The length of the 400 g rod is nearly:

Option 1 - <p><span lang="EN-IN">8.5 cm</span></p>
Option 2 - <p><span lang="EN-IN">17.5 cm</span></p>
Option 3 - <p><span lang="EN-IN">20.7 cm</span></p>
Option 4 - <p><span lang="EN-IN">72.0 cm</span></p>
2 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
7 months ago
Correct Option - 1
Detailed Solution:

Moment of inertia of r o d = I = m l 2 1 2

2 4 0 0 = 4 0 0 l 2 1 2

7 2 = l 2

l=72=8.48 cm=8.5 cm

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Physics System of Particles and Rotational Motion 2025

Physics System of Particles and Rotational Motion 2025

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