The motion of a simple pendulum executing S.H.M. is represented by the following equation. <math><mrow><mi>y</mi><mo>=</mo><mi>A</mi><mi>s</mi><mi>i</mi><mi>n</mi><mrow><mo>(</mo><mrow><mi>π</mi><mi>t</mi><mo>+</mo><mi>?</mi></mrow><mo>)</mo></mrow><mo>,</mo></mrow></math> where time is measured in second. The length of pendulum is

According to question, we can writeω=π=gl⇒l=gπ2=9.8 (3.14)2=0.99395 =99.4cm

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Simple Harmonic Motion Physics Oscillations Physics Class 11th

The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A s i n (π t + ?),$ where time is measured in second. The length of pendulum is

Option 1 -

97.23 cm

Option 2 -

25.3 cm

Option 3 -

99.4 cm

Option 4 -

406.1 cm

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Payal Gupta | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

According to question, we can write

$ω = π = \sqrt[]{\frac{g}{l}} \Rightarrow l = \frac{g}{π^{2}} = \frac{9.8}{{(3.14)}^{2}} = 0.99395 = 99.4 c m$

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The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A s i n (π t + ?),$ where time is measured in second. The length of pendulum is

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The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A s i n (π t + ?),$ where time is measured in second. The length of pendulum is