Class 11th physics ncert solutions class 11th Kinetic Theory Physics

**The number of molecules in one litre of an ideal gas at 300K and 2 atmospheric pressure with mean kinetic energy 2 * 10?? J per molecule is:**

Option 1 - <p>0.75 × 10¹¹<br><br></p>

Option 2 - <p>3 × 10¹¹<br><br></p>

Option 3 - <p>6 × 10¹¹<br><br></p>

Option 4 - <p>1.5 × 10¹¹</p>

101 Views|Posted 5 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

5 months ago

Correct Option - 3

Detailed Solution:

1 litre, T = 300K, P = 2 atm, KE = 2*10? J/molecule, no of molecule =?
No. of molecules = (no of moles) * NA = nNA
Also, n = PV/RT = PV/ (NAkT)
KE = (3/2)kT = 2*10? J [Given]
kT = (4/3)*10?
P = 2 atm = 2 * 1.013 * 10? N/m²
vol = 1 lit = 10? ³ m³
No. of molecules = PV/kT = (2*1.013*10? * 10? ³)/ (4/3)*10?

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physics ncert solutions class 11th 2023

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