The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 × 10⁻³
watt will be : h = 6.6 × 10⁻³⁴Js)
The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 × 10⁻³
watt will be : h = 6.6 × 10⁻³⁴Js)
Option 1 -
10¹⁸
Option 2 -
10¹⁷
Option 3 -
10¹⁶
Option 4 -
10¹⁵
Asked by Shiksha User
-
1 Answer
-
Correct Option - 3
Detailed Solution:p = nhc/λ ⇒ n = pλ/hc
n = (3.3 × 10? ³ × 600 × 10? ) / (6.6 × 10? ³? × 3 × 10? ) = 10¹?
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers