The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72nd division on circular scale coincides with the reference line, The radius of the wire is:

Option 1 -

0.82mm

Option 2 -

1.63mm

Option 3 -

0.90mm

Option 4 -

1.80mm

0 1 View | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    L C = 1 1 0 0 m m = 0 . 0 1 m m

    Zero error = +0.08 mm.

    Diameter = 1 + 72 * 0.01 – 0.08 = 1.64 mm

    Radius = 0.82 mm

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