The point A moves with a uniform speed along the circumference of a circle of radius 0.36m and covers 30° in 0.1s. The perpendicular projection 'P' from 'A' n the diameter MN represents the simple harmonic motion of 'P'. The restoration force per unit mass when P touches M will be
The point A moves with a uniform speed along the circumference of a circle of radius 0.36m and covers 30° in 0.1s. The perpendicular projection 'P' from 'A' n the diameter MN represents the simple harmonic motion of 'P'. The restoration force per unit mass when P touches M will be
Option 1 - <p>100N</p>
Option 2 - <p>50N</p>
Option 3 - <p>9.87N</p>
Option 4 - <p>0.49N</p>
4 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
Answered by
6 months ago
Correct Option - 3
Detailed Solution:
As we know that maximum acceleration will act on the particle when it is at extreme position .
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics Oscillations 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering






