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Class 11thPhysics Motion in Straight LinePhysics

The position, velocity and acceleration of a particle moving with a constant acceleration can be represented by:

Option 1 - <p>Position: x(t) is a curve increasing with increasing slope. Velocity: v(t) is a straight line with positive slope. Acceleration: a(t) is a constant positive line.<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>Position: x(t) is a curve increasing with decreasing slope. Velocity: v(t) is a straight line with positive slope. Acceleration: a(t) is a constant positive line.<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>Position: x(t) is a curve increasing with decreasing slope. Velocity: v(t) is a straight line with negative slope. Acceleration: a(t) is a constant negative line.<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>Position: x(t) is a curve increasing with increasing slope. Velocity: v(t) is a straight line with positive slope. Acceleration: a(t) is a constant positive line that changes value over time.</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 1
Detailed Solution:

For constant acceleration, a,
x = ut + (1/2)at² ⇒ x-t graph is parabola.
v = u + at ⇒ v-t graph is straight line with positive slope.

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