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The position x of a particle of mass 2 kg moving along straight line is given as x = (t – 2)2, where t is in second and x is in metre. The work done by the force in first 2 s is

Option 1 -

0 J

Option 2 -

–16 J

Option 3 -

16 J

Option 4 -

32 J

0 1 View | Posted a week ago
Asked by Shiksha User

  • 1 Answer

  • Correct Option - 2


    Detailed Solution:
    Kindly go through the solution

     

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