The potential energy of a body of mass 3 kg on the surface of a planet is 54 joule. The escape velocity will be

Option 1 -  18 m/s

Option 2 - 162 m/s

Option 3 - 36 m/s

Option 4 - 6 m/s

2 Views|Posted 4 months ago

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Answered by

Raj Pandey | Contributor-Level 9

4 months ago

Correct Option - 4

Detailed Solution:

By given $U = 54 joule m = 3 kg$

By conservation of mechanical energy law

$(K + U)$ Earth surface $= (K + U) \infty$

$\frac{1}{2} m v^{2} + (- 54 J) = 0 + 0$

$\frac{1}{2} m v^{2} = 54$

$3 v^{2} = 108$

$v^{2} = \frac{108}{3} = 36$

v= 6m/s

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