The radius of a sphere is measured to be (7.50±0.85) cm. Suppose the percentage error in its volume is x. The value of x, to the nearest integer, is..................
The radius of a sphere is measured to be (7.50±0.85) cm. Suppose the percentage error in its volume is x. The value of x, to the nearest integer, is..................
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1 Answer
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V = (4/3)πr³
⇒ ΔV/V = 3 (Δr/r) ⇒ Relative error
% error in volume = (ΔV/V) × 100 = 3 (Δr/r) × 100 = 3 × (0.85/7.50) × 100 = 33.999 ≈ 34
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