The refracting angle of a prims is  A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be

Option 1 - <p>180 - 2A&nbsp;&nbsp;</p>
Option 2 - <p>90 - A&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p>180&nbsp; + 2A&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 4 - <p>180 - 3A</p>
6 Views|Posted 6 months ago
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1 Answer
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6 months ago
Correct Option - 1
Detailed Solution:

At minimum deviation –

δ=2iAi=δ+A2, r=A2

Using snell's low : - sini=μ=sinr

δ+A2=πA2δ=π2A

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Physics NCERT Exemplar Solutions Class 12th Chapter Nine 2025

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