Class 11th physics ncert solutions class 11th Kinetic Theory Physics

The rms speed of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are $V_{H}, V_{O} a n d V_{C}$ respectively then:

Option 1 - <p>V<sub>C</sub> > V<sub>O</sub> > V<sub>H</sub>    </p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>H</mi> </mrow> </msub> <mo>></mo> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>O</mi> </mrow> </msub> <mo><</mo> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> </mrow> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>H</mi> </mrow> </msub> <mo>=</mo> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>O</mi> </mrow> </msub> <mo>=</mo> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> </mrow> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>H</mi> </mrow> </msub> <mo>=</mo> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>O</mi> </mrow> </msub> <mo>></mo> <msub> <mrow> <mi>V</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> </mrow> </math> </span></p>

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 2

Detailed Solution:

$V_{r m s} = \sqrt[]{\frac{3 R T}{M}}$

$V_{r m s} \propto \frac{1}{\sqrt[]{M}}$ at constant T

$V_{H} : V_{O} : V_{C o_{2}} = \frac{1}{\sqrt[]{1}} : \frac{1}{\sqrt[]{16}} : \frac{1}{\sqrt[]{44}}$

$= 1 : \frac{1}{4} : \frac{1}{2 \sqrt[]{11}}$

$V_{H} > V_{O} > V_{C O_{2}}$

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physics ncert solutions class 11th 2023

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