The rms speed of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are $V_{H}, V_{O} a n d V_{C}$ respectively then:

Option 1 -

V_C > V_O > V_H

Option 2 -

$V_{H} > V_{O} < V_{C}$

Option 3 -

$V_{H} = V_{O} = V_{C}$

Option 4 -

$V_{H} = V_{O} > V_{C}$

5 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

$V_{r m s} = \sqrt[]{\frac{3 R T}{M}}$

$V_{r m s} \propto \frac{1}{\sqrt[]{M}}$ at constant T

$V_{H} : V_{O} : V_{C o_{2}} = \frac{1}{\sqrt[]{1}} : \frac{1}{\sqrt[]{16}} : \frac{1}{\sqrt[]{44}}$

$= 1 : \frac{1}{4} : \frac{1}{2 \sqrt[]{11}}$

$V_{H} > V_{O} > V_{C O_{2}}$

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The rms speed of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are $V_{H}, V_{O} a n d V_{C}$ respectively then:

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The rms speed of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are V H , V O a n d V C respectively then:

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The rms speed of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are $V_{H}, V_{O} a n d V_{C}$ respectively then: