Ask & Answer Question

Physics Gravitation Physics Class 11th Gravitation

The satellites revolve around a planet in coplanar circular orbits in anticlockwise direction. Their period of revolutions are 1 hour and 8 hour respectively. The radius of the orbit of nearer satellite is 2 × 10³ km. The angular speed of the farther satellite as observed from the nearer satellite at the instant when both the satellites are closest is $\frac{π}{x} r a d h^{- 1}$ where x is__________.

2 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

For A satellite T₁ = 1hour

$S o ω_{1} = 2 π r e d / h o u r$

for B satellite T₂ = 8 hour

given R₁ = 2 × 10³ Km

Relative $ω = \frac{V_{1} - V_{2}}{R_{2} - R_{1}} = \frac{2 π \times 1 0^{3}}{6 \times 1 0^{3}}$

$\Rightarrow \frac{π}{3}$ rad/hour

x = 3

0 Upvotes 0 Downvotes

Similar Questions for you

The height at which the weight of an object becomes (1/16)^th of its weight on the surface of earth is (R is radius of earth)

alok kumar singh

In the equation of angular displacement of a particle moving on a circular path is given as is in radian and t in second. Theq angular velocity of the particle at t = 2 s is

alok kumar singh

If an object is having same weight at same distance above and below the surface of earth, find its distance from surface of earth.

alok kumar singh

$\frac{G M m}{{(R + x)}^{2}} = \frac{G M m (R - x)}{R^{3}}$

->R³ = (R + x)² (R – x)

->R³ = (R²– x²) (R + x)

->x² + Rx – R² = 0

$x = \frac{- R \pm \sqrt[]{R + 4 R^{2}}}{2}$

$x = \frac{(\sqrt[]{5 R} - 1)}{2} R$

Two bodies of mass $m$ and $9 m$ are placed at a distance $R$ . The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be ( $G =$ gravitational constant):

alok kumar singh

Stress $= \frac{F}{A} = \frac{T}{A} = \frac{W}{A}$

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : The escape velocities of planet Ad and B are same. But A and B are of unequal mass.

Reason R : The product of their mass and radius must be same. M₁ R₁ = M₂R₂

In the light of the above statements, choose the most appropriate answer from the options given below:

Vishal Baghel

${(v_{e})}_{A} = {(v_{e})}_{B} \Rightarrow \frac{M_{1}}{R_{1}} = \frac{M_{2}}{R_{2}}$

R is not correct.

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
688k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question