The time period of a simple pendulum is given by T = 2π√(l/g). The measured value of the length of pendulum is 10cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of 'g' using this pendulum is 'x'. The value of 'x' to the nearest integer is,

Option 1 - <p>4%<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>3%</p>
Option 3 - <p>2%</p>
Option 4 - <p>5%</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 4
Detailed Solution:

l = 10.0 ± 0.1cm.
T = (100 ± 1) / 200 = 0.5 ± 0.005

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Physics Units and Measurement 2025

Physics Units and Measurement 2025

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