The time period of a simple pendulum is given by T = 2π√(l/g). The measured value of the length of pendulum is 10cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of 'g' using this pendulum is 'x'. The value of 'x' to the nearest integer is,
The time period of a simple pendulum is given by T = 2π√(l/g). The measured value of the length of pendulum is 10cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of 'g' using this pendulum is 'x'. The value of 'x' to the nearest integer is,
Option 1 -
4%
Option 2 -
3%
Option 3 -
2%
Option 4 -
5%
Asked by Shiksha User
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1 Answer
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Correct Option - 4
Detailed Solution:l = 10.0 ± 0.1cm.
T = (100 ± 1) / 200 = 0.5 ± 0.005
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