The variation of displacement with time of a particle executing free simple harmonic moton is shown in the figure. The potential energy U(x) versus time (t) plot of the particle is correctly shown in figure:
The variation of displacement with time of a particle executing free simple harmonic moton is shown in the figure. The potential energy U(x) versus time (t) plot of the particle is correctly shown in figure:
Potential Energy is maximum at extreme position
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Velocity of block in equilibrium, in first case,
Velocity of block in equilibrium, is second case,
From conservation of momentum,
Mv = (M + m) v’
f? = 300 Hz
3rd overtone = 7f? = 2100 Hz
Kindly consider the following figure
K = U
½ mω² (A² - x²) = ½ mω²x²
A² - x² = x²
A² = 2x²
x = ± A/√2
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Physics Oscillations 2025
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