The velocity-displacement graph of a particle is shown in the figure. The acceleration-displacement graph of the same particle is represented by :
The velocity-displacement graph of a particle is shown in the figure. The acceleration-displacement graph of the same particle is represented by :
Option 1 - <p>a</p>
Option 2 - <p>b</p>
Option 3 - <p>c</p>
Option 4 - <p>d</p>
8 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 3
Detailed Solution:
(v/v? ) + (x/x? ) = 1 ⇒ v = - (v? /x? )x + v?
⇒ a = dv/dt = - (v? /x? ) (v) = - (v? /x? ) [- (v? /x? )x + v? ] ⇒ a = (v? ²/x? ²)x - v? ²/x?
- Concept involved: Graph of kinematics
- Topic: Kinematics
- Difficulty level: Moderate
- Note: IIT-Jee-2005
- Point of Error: Writing Equation of straight line and differe
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics Work, Energy and Power 2021
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering







