The velocity of a particle is v = v₀ + gt + Ft². Its position is x = 0 at t = 0; then its displacement after time (t = 1) is:
The velocity of a particle is v = v₀ + gt + Ft². Its position is x = 0 at t = 0; then its displacement after time (t = 1) is:
Option 1 -
v₀ + g/2 + F/3
Option 2 -
v₀ + g/2 + F
Option 3 -
v₀ + 2g + 3F
Option 4 -
v₀ + g + F
-
1 Answer
-
Correct Option - 1
Detailed Solution:The displacement S is calculated by integrating the velocity function:
S = x - x? = ∫? ¹ v dt = ∫? ¹ (v? + gt + Ft²) dt = v? + g/2 + F/3
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers