The velocity (v) and time (t) graph of a body in a straight line motion is shown in the figure. The point S is at 4.333 seconds. The total distance covered by the body in 6 s is:
The velocity (v) and time (t) graph of a body in a straight line motion is shown in the figure. The point S is at 4.333 seconds. The total distance covered by the body in 6 s is:
Option 1 -
11 m
Option 2 -
37/3 m
Option 3 -
12 m
Option 4 -
49/4 m
Asked by Shiksha User
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1 Answer
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Correct Option - 2
Detailed Solution:Area of OABS is A?
Area of SCD is A?
Distance = |A? | + |A? |
A? = (1/2) [13/3 + 1]4 = 32/3
A? = (1/2) × 5/3 × 2 = 5/3
Distance = |A? | + |A? |
= 32/3 + 5/3 = 37/3
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