The vertical component of the earth’s magnetic field is 6 × 10^-5 T at any place where the angle of dip is 37°. The earth’s resultant magnetic field at that place will be (Given tan37° = $\frac{3}{4}$ )

Correct Option - 4


Detailed Solution:

B_v = 6 × 10^-5 T

B_v = B_N sin37°

$\therefore B_N=\frac{B_v}{sin37°}=\frac{6\times 10^{-5}}{3/5}=10^{-4}T$

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