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**The x-t graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at t=2 is:**

Option 1 -

$- \frac{π^{2}}{16} {m s}^{- 2}$

Option 2 -

$\frac{π^{2}}{8} {m s}^{- 2}$

Option 3 -

$- \frac{π^{2}}{8} {m s}^{- 2}$

Option 4 -

$\frac{π^{2}}{16} {m s}^{- 2}$

2 Views | Posted 3 weeks ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

3 weeks ago

Correct Option - 1

Detailed Solution:

From x-t graph,

$\begin{array}{r} A = 1, T = 8 \\ \Rightarrow ω = \frac{2 π}{T} \\ \Rightarrow ω = \frac{π}{4} \\ at t = 2, x = 1 \\ a = - ω^{2} x \\ \Rightarrow a = \frac{- π^{2}}{16} \times 1 \\ \Rightarrow a = \frac{- π^{2}}{16} m / s^{2} \end{array}$

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**The x-t graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at t=2 is:**

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