Thermodynamic process is shown below on a P-V diagram for one mole of an ideal gas. If V2 = 2V1 then the ratio of temperature T2/T1 is

Thermodynamic process is shown below on a P-V diagram for one mole of an ideal gas. If V₂ = 2V₁ then the ratio of temperature T₂/T₁ is

Option 1 - 2

Option 2 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> </mrow> </mfrac> </mrow> </math>

Option 3 - <math> <mrow> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math>

Option 4 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math>

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Answered by

Payal Gupta | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

Since equation of the gas process is given so we can convert it into T & V form.

$P V^{\frac{1}{2}} = C$

$\Rightarrow \frac{T}{\sqrt[]{V}} = C$

$\Rightarrow \frac{T_{1}}{V_{1}} = T_{2}$ $V_{2}$

$\Rightarrow \frac{T_{1}}{T_{2}} =$ = $\frac{1}{\sqrt[]{2}}$

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