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Three capacitors each of capacitance C = 2μF are connected with a battery of emf 30V as shown in the figure. When the switch S is closed, the heat generated in circuit will be n/10 mJ. Find the value of n.

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago

    Ui = ½C (V/3)² + ½C (V/3)² + ½C (2V/3)²
    Uf = ½CV²
    Wb = CV²/3
    ΔH = [Wb - (Uf - Ui)] = CV²/6 = 0.30 mJ

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