Total charge -Q is uniformly spread along the length of a ring of radius R. A small test charge +q of mass m is kept at the centre of the ring and is given a gentle push along the axis of the ring.
(a) Show that the particle executes a simple harmonic oscillation.
(b) Obtain its time period.
Total charge -Q is uniformly spread along the length of a ring of radius R. A small test charge +q of mass m is kept at the centre of the ring and is given a gentle push along the axis of the ring.
(a) Show that the particle executes a simple harmonic oscillation.
(b) Obtain its time period.
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1 Answer
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This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- electric field at the axis of the ring is E=KQy/ (R2+z2)3/2 where z is distance .
F=qE=KQqy/ (R2+z2)3/2
When z<
F= = -Kz
So force is directly proportional to – distance that is completely defined that is follows S.H.M
(b)w=
T=2 w=2
T=2
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