Two cells of voltage 10 V and 2 V, and internal resistances 10 Ω  and 5 Ω respectively, are connected in parallel with the positive end of 10 V battery connected to negative pole of 2 V battery (figure). Find the effective voltage and effective resistance of the combination.

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    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    Explanation- applying kirchhoff's junction rule I1 = I+I2

    Applying kirchhoff's rule in outer loop containing 10V cell

    10= IR+10I1……………. (1)

    Applying kirchhoff's rule in outer loop containing 2V cell

    2= 5I2-RI= 5 (I1-I)-RI

    4= 10I1-10I-RI………… (2)

    From 1 and 2

    6=3RI+10I

    2=I (R+10/3)

    V= I (R+Reff)

    After comparing V=2V, Reff= 10/3 ohm

    Since effective internal resistance Reff of two cells 10/3 ohm, being the parallel combination 5 ohm and 10 ohm . the equivalent circuit is

     

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