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Two circular rings (of same material) are of same thickness. The diameter of first ring is twice that of second. The moment of inertia of first ring as compared to that of second is

Option 1 -

4 times

Option 2 -

8 times

Option 3 -

16 times

Option 4 -

2 times

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 2


    Detailed Solution:

    l 1 l 2 = M 1 R 1 2 M 2 R 2 2 = ρ × 2 π R 1 × R 1 2 ρ × 2 π R 2 × R 2 2 = R 1 3 R 2 3 = 8 1

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