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Two coils of self inductance L1 and L2 are connected in series combination having mutual inductance of the coils as M. The equivalent self inductance of the combination will be:

Option 1 -

1 L 1 + 1 L 2 + 1 M

Option 2 -

L 1 + L 2 + M

Option 3 -

L1 + L2 + 2M

Option 4 -

L1 + L2 – 2M

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

     Leq=L1+L2−2M

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